Question

how many grams of pbso₄ would be produced from the complete reaction of 23.6 g pbo₂?
pb + pbo₂ + 2h₂so₄ → 2pbso₄ + 2h₂o
pbo₂ : 239.2 g/mol
pbso₄ : 303.27 g/mol ? g pbso₄

Explanation:

Step1: Calculate moles of \( \text{PbO}_2 \)

Moles of \( \text{PbO}_2 = \frac{\text{mass of } \text{PbO}_2}{\text{molar mass of } \text{PbO}_2} \)
\( \text{Moles of } \text{PbO}_2 = \frac{23.6\ \text{g}}{239.2\ \text{g/mol}} \approx 0.09866\ \text{mol} \)

Step2: Determine mole ratio of \( \text{PbO}_2 \) to \( \text{PbSO}_4 \)

From the balanced equation: \( \text{Pb} + \text{PbO}_2 + 2\text{H}_2\text{SO}_4
ightarrow 2\text{PbSO}_4 + 2\text{H}_2\text{O} \)
The mole ratio of \( \text{PbO}_2 \) to \( \text{PbSO}_4 \) is \( 1:2 \).

Step3: Calculate moles of \( \text{PbSO}_4 \)

Moles of \( \text{PbSO}_4 = 2 \times \text{moles of } \text{PbO}_2 \)
\( \text{Moles of } \text{PbSO}_4 = 2 \times 0.09866\ \text{mol} = 0.19732\ \text{mol} \)

Step4: Calculate mass of \( \text{PbSO}_4 \)

Mass of \( \text{PbSO}_4 = \text{moles of } \text{PbSO}_4 \times \text{molar mass of } \text{PbSO}_4 \)
\( \text{Mass of } \text{PbSO}_4 = 0.19732\ \text{mol} \times 303.27\ \text{g/mol} \approx 59.8\ \text{g} \)

Answer:

\( \approx 59.8\ \text{g} \)