Question

how many formula units (f.un.) are in 35.0 g kno₃? (1 mol kno₃ = 101.11 g) (1 mol kno₃ = 6.02 × 10²³ formula units) ?×10^? f.un. kno₃ enter the coefficient in the green box and the exponent in the yellow box. coefficient (green) exponent (yellow) submit

Explanation:

Step1: Calculate moles of \( \text{KNO}_3 \)

Moles = \( \frac{\text{Mass}}{\text{Molar Mass}} \) = \( \frac{35.0\ \text{g}}{101.11\ \text{g/mol}} \) ≈ \( 0.3461\ \text{mol} \)

Step2: Calculate formula units

Formula units = Moles × Avogadro's number = \( 0.3461\ \text{mol} × 6.02×10^{23}\ \text{f.un./mol} \) ≈ \( 2.083×10^{23}\ \text{f.un.} \)

Answer:

Coefficient (green): \( 2.08 \) (or more precise \( 2.083 \)), Exponent (yellow): \( 23 \)
So the answer is \( \boldsymbol{2.08}×10^{\boldsymbol{23}} \) f.un. \( \text{KNO}_3 \) (or with more precision \( 2.083×10^{23} \))