how many atoms of na are present in 1.15 moles of sodium? 6.02 x 10^{24} atoms na 6.92 x 10^{23} atoms na 9.11 x 10^{25} atoms na 6.92 x 10^{21} atoms na

Question

Accepted Answer

# Explanation:
## Step1: Recall Avogadro's number
Avogadro's number $ N_A=6.02\times 10^{23}\text{ atoms/mol}$
## Step2: Use the formula $N = n\times N_A$
Here, $n = 1.15\space mol$ (moles of $Na$), $N_A = 6.02\times 10^{23}\text{ atoms/mol}$
$$
\begin{align*}
N&=1.15\space mol\times6.02\times 10^{23}\text{ atoms/mol}\
&=(1.15\times6.02)\times10^{23}\text{ atoms}\
&= 6.923\times10^{23}\text{ atoms}\approx6.92\times 10^{23}\text{ atoms}
\end{align*}
$$

# Answer:
$6.92\times 10^{23}\text{ atoms Na}$ (the second option)

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Question

Explanation:

Step1: Recall Avogadro's number

Step2: Use the formula \(N = n\times N_A\)

Answer: