Question

homework 3
q1a. define work in physics
b. under what condition is work positive.
c. give one real - life example of positive, negative and zero work
q2. a student pushes a box with a 50n force over a 3m distance along the floor. this force make an angle of 30° with the horizontal find the work done by the studen

Explanation:

Step1: Write the formula for work

The formula for work \(W\) is \(W = Fd\cos\theta\), where \(F\) is the force applied, \(d\) is the displacement, and \(\theta\) is the angle between the force and the displacement.

Step2: Substitute the given values into the formula

Given \(F = 50\space N\), \(d=3\space m\), and \(\theta = 30^{\circ}\). We know that \(\cos30^{\circ}=\frac{\sqrt{3}}{2}\approx0.866\).
Substitute these values into the formula: \(W=(50)(3)\cos30^{\circ}\)

Step3: Calculate the work

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Answer:

The work done by the student is approximately \(130\space J\)