Question

he center - radius form of the equation of the circle is $x^{2}+y^{2}=169$.
(ee an equation.)
use the graphing tool to graph the circle.
click to
enlarge
graph
click the graph, choose a tool in the palette and follow the instr...

Explanation:

Step1: Recall the center - radius form of a circle

The standard form of a circle's equation is \((x - h)^2+(y - k)^2=r^2\), where \((h,k)\) is the center and \(r\) is the radius.
For the equation \(x^{2}+y^{2}=169\), we can rewrite it as \((x - 0)^2+(y - 0)^2 = 13^{2}\). So the center \((h,k)=(0,0)\) and radius \(r = 13\).

Step2: Plot the circle

• Mark the center at the origin \((0,0)\) on the coordinate plane.
• From the center, move 13 units up, down, left, and right. These points \((0,13)\), \((0, - 13)\), \((13,0)\), \((-13,0)\) are on the circle.
• Use a graphing tool (in this case, the one provided in the interface) to draw a smooth curve passing through these four points and all other points that are 13 units away from the origin.

Answer:

Use the graphing tool to plot a circle with center \((0,0)\) and radius \(13\). Mark the center at the origin, then use the radius to find four key points \((0,\pm13)\) and \((\pm13,0)\) and draw the circle passing through them.