Question

having problems staying logged in or are you experiencing issues? please visit our troubleshooting section for solutions. analyze this: a frictional force of 45.7 n acts upon a 5.37 kg rightward - moving box to accelerate it leftward. complete the diagram. tap on a field to enter or edit its value. units force: n mass: kg acceln: m/s/s

Explanation:

Step1: Find \( F_{grav} \)

Using \( F_{grav}=mg \), where \( m = 5.37\ \text{kg} \) and \( g = 9.8\ \text{m/s}^2 \).
\( F_{grav}=5.37\times9.8 = 52.626\ \text{N} \)

Step2: Find \( F_{norm} \)

Since there is no vertical acceleration, \( F_{norm}=F_{grav} \).
\( F_{norm}=52.626\ \text{N} \)

Step3: Find \( F_{net} \)

The only horizontal force is \( F_{frict} \), so \( F_{net}=F_{frict}=45.7\ \text{N} \) (leftward)

Step4: Find \( a \)

Using \( F_{net}=ma \), so \( a=\frac{F_{net}}{m} \).
\( a=\frac{45.7}{5.37}\approx8.51\ \text{m/s}^2 \) (leftward)

Answer:

\( F_{grav}=52.6\ \text{N} \), \( F_{norm}=52.6\ \text{N} \), \( m = 5.37\ \text{kg} \), \( a\approx8.51\ \text{m/s}^2 \), \( F_{net}=45.7\ \text{N} \)