Question

a hat has 6 coins: 5 quarters, 1 nickel. if 1 coin is drawn, replaced, and 1 is drawn again, what is the probability of drawing a quarter, then a nickel? event a: quarter on 1st draw event b: nickel on 2nd draw p(a, then b) = ?/? give your answer as a fraction in simplest form. compound probability independent events p(a then b) = p(a) · p(b)

Explanation:

Step1: Calculate P(A)

Probability of drawing a quarter: $\frac{5}{6}$

Step2: Calculate P(B)

Probability of drawing a nickel: $\frac{1}{6}$

Step3: Multiply probabilities

$P(A \text{ then } B) = P(A) \cdot P(B) = \frac{5}{6} \cdot \frac{1}{6} = \frac{5}{36}$

Answer:

$\frac{5}{36}$