Question

6.2 grouping: problem 1
(1 point)
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factor:
3a(s - 3t) + 4b(s - 3t) + 4(s - 3t) =
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Explanation:

Step1: Factor out the common term

The common term in the expression \(3a(s - 3t)+4b(s - 3t)+4(s - 3t)\) is \((s - 3t)\).
Using the distributive property \(ac+bc+dc=(a + b + d)c\) (where \(c=(s - 3t)\), \(a = 3a\), \(b = 4b\), \(d = 4\)), we get \((s-3t)(3a + 4b+4)\).

Answer:

\((s - 3t)(3a + 4b + 4)\)