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in a group of students, 61 play soccer, 56 play basketball, and 72 run …

Question

in a group of students, 61 play soccer, 56 play basketball, and 72 run track.
what is the probability that a randomly selected student doesnt run track?
\\(p(\text{doesnt run track}) = \\ ?\\ \\%\\)
round your answer to the nearest whole percent.

Explanation:

Calculate total students

We find the total number of students in the group.
Using the Theoretical Probability knowledge point:

$$ \text{Total} = 61 + 56 + 72 = 189 $$

Find students not running track

We find the number of students who do not run track.
Using the Complementary Probability knowledge point:

$$ \text{Not Track} = 189 - 72 = 117 $$

Calculate the probability

We compute the probability as a fraction.
Using the Theoretical Probability knowledge point:

$$ P(\text{doesn't run track}) = \frac{117}{189} $$

Convert to percentage

We convert the fraction to a percentage.

$$ \frac{117}{189} \approx 0.619047 $$
$$ 0.619047 \times 100\% \approx 61.9\% $$

Round to nearest whole percent

We round the percentage to the nearest integer.

$$ 61.9\% \approx 62\% $$

Answer:

In a group of students, 61 play soccer, 56 play basketball, and 72 run track. What is the probability that a randomly selected student doesn't run track?

\(P(\text{doesn't run track}) =\) <blank>62</blank>%

Round your answer to the nearest whole percent.