Question

the graphs below model two transverse waves that maya created with a battle rope. in each graph, the horizontal axis shows the horizontal position of particles of the rope, measured from where maya stood. the vertical axis shows the vertical displacement of the rope, measured from the equilibrium position, at a specific moment in time. wave 1 wave 2 assuming the waves are traveling at the same speed, compare the waves. the amplitude is the wavelength is the frequency is

Explanation:

Step1: Determine the amplitude

Amplitude is the maximum displacement from the equilibrium position. For Wave 1, the maximum displacement is \(2\) units. For Wave 2, the maximum displacement is \(1.5\) units. So, the amplitude is greater for Wave 1.

Step2: Determine the wavelength

Wavelength is the distance between two consecutive crests (or troughs). For Wave 1, from \(0\) to \(10\) (one full wave cycle) is \(10\) units. For Wave 2, from \(0\) to \(5\) is half a wave cycle, so a full wave cycle is \(5\times2 = 5\) units. So, the wavelength is greater for Wave 1.

Step3: Use the wave - speed formula \(v=\lambda f\)

Since \(v\) (speed) is the same for both waves (\(v_1 = v_2\)), and \(v=\lambda f\). If \(\lambda_1>\lambda_2\) (from Step 2), then \(f_1

Answer:

The amplitude is greater for Wave 1.
The wavelength is greater for Wave 1.
The frequency is greater for Wave 2.