Question

1. graph $\triangle jkl$ with vertices $j(-2, 8)$, $k(1, -3)$, and $l(5, 4)$ and its image after the composition.

translation: $(x, y) \to (x + 6, y - 1)$
translation: $(x, y) \to (x - 1, y - 7)$

Explanation:

Step1: Apply first translation to J

$J(-2,8) \to (-2+6,8-1) = (4,7)$

Step2: Apply first translation to K

$K(1,-3) \to (1+6,-3-1) = (7,-4)$

Step3: Apply first translation to L

$L(5,4) \to (5+6,4-1) = (11,3)$

Step4: Apply second translation to J'

$J'(4,7) \to (4-1,7-7) = (3,0)$

Step5: Apply second translation to K'

$K'(7,-4) \to (7-1,-4-7) = (6,-11)$

Step6: Apply second translation to L'

$L'(11,3) \to (11-1,3-7) = (10,-4)$

Answer:

Vertices of the final image: $J''(3,0)$, $K''(6,-11)$, $L''(10,-4)$
(Graphing requires plotting original points $J(-2,8), K(1,-3), L(5,4)$ and final image points $J''(3,0), K''(6,-11), L''(10,-4)$ on a coordinate plane.)