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Question
graph the solution to the inequality on the number line.
$|2x - 8|\leq12$
Step1: Remove absolute value
$$-12\leq 2x - 8\leq 12$$
Step2: Add 8 to each part
$$-12 + 8\leq 2x-8 + 8\leq 12 + 8$$
$$-4\leq 2x\leq 20$$
Step3: Divide each part by 2
$$\frac{-4}{2}\leq\frac{2x}{2}\leq\frac{20}{2}$$
$$-2\leq x\leq 10$$
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On the number - line, draw a solid circle at \(x = - 2\) and \(x = 10\) (because the inequality includes equality, \(\leq\)) and shade the region between them.