Question

graph the solution to the following inequal
$-x^{2}+4x < -5$

Explanation:

Step1: Solve the inequality

$$\begin{align*} -x + 2&<4x-5\\ -x-4x&<-5 - 2\\ -5x&<-7\\ x&>\frac{7}{5} = 1.4 \end{align*}$$

Step2: Graph the solution

Since \(x>1.4\), we draw an open circle at \(x = 1.4\) (because the inequality is strict, \(x
eq1.4\)) and shade the region to the right of \(1.4\) on the number line.

Answer:

Graph an open circle at \(x = 1.4\) and shade the region to the right of \(1.4\) on the number line.