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Question
graph a right triangle with the two points forming the hypotenuse. using the sides, find the distance between the two point simplest radical form.
(2, -3) and (-1, 1)
click twice to draw a line. click a segment to erase it.
answer
leg 1: leg 2: hypotenuse:
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Step1: Find horizontal distance (Leg 1)
The x - coordinates of the points are \(2\) and \(- 1\). The horizontal distance (difference in x - values) is \(|2-(-1)|=|2 + 1|=3\).
Step2: Find vertical distance (Leg 2)
The y - coordinates of the points are \(-3\) and \(1\). The vertical distance (difference in y - values) is \(|1-(-3)|=|1 + 3| = 4\).
Step3: Find hypotenuse (distance)
Using the Pythagorean theorem \(c=\sqrt{a^{2}+b^{2}}\), where \(a = 3\) and \(b = 4\). So \(c=\sqrt{3^{2}+4^{2}}=\sqrt{9 + 16}=\sqrt{25}=5\).
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Leg 1: \(3\)
Leg 2: \(4\)
Hypotenuse: \(5\)