Question

graph the parabola.

\\( y = -2x^2 \\)

plot five points on the parabola: the vertex, two points to the left of the vertex, and two points to the right of the vertex. then click on the graph-a-function button.

Explanation:

Step1: Find the vertex

For $y=-2x^2$, vertex is $(0,0)$ (since $x=-\frac{b}{2a}=0$, $y=0$).

Step2: Calculate left points ($x=-1,-2$)

$x=-1$: $y=-2(-1)^2=-2$ → $(-1,-2)$
$x=-2$: $y=-2(-2)^2=-8$ → $(-2,-8)$

Step3: Calculate right points ($x=1,2$)

$x=1$: $y=-2(1)^2=-2$ → $(1,-2)$
$x=2$: $y=-2(2)^2=-8$ → $(2,-8)$

Answer:

Plot points: $(0,0)$, $(-1,-2)$, $(-2,-8)$, $(1,-2)$, $(2,-8)$ then draw the parabola.