Question

graph the image of square pqrs after a translation 9 units right.

Explanation:

Step1: Recall translation rule

For a translation 9 units right, we add 9 to the x - coordinate of each vertex.

Step2: Identify original vertices

Assume \(P(-6,2)\), \(Q(-2,2)\), \(R(-2,6)\), \(S(-6,6)\).

Step3: Calculate new vertices

For \(P\): New \(x=-6 + 9=3\), \(y = 2\), so \(P'(3,2)\).
For \(Q\): New \(x=-2 + 9 = 7\), \(y = 2\), so \(Q'(7,2)\).
For \(R\): New \(x=-2+9 = 7\), \(y = 6\), so \(R'(7,6)\).
For \(S\): New \(x=-6 + 9=3\), \(y = 6\), so \(S'(3,6)\).

Step4: Graph new square

Plot \(P'(3,2)\), \(Q'(7,2)\), \(R'(7,6)\), \(S'(3,6)\) and connect them to form the new square.

Answer:

Graph the square with vertices \(P'(3,2)\), \(Q'(7,2)\), \(R'(7,6)\), \(S'(3,6)\) on the given coordinate - plane.