Question

graph the image of parallelogram ( jklm ) after a reflection over the line ( y=-x ).

Explanation:

Step1: Find coordinates of original points

Assume \(J(-9,-10)\), \(K(-6,-10)\), \(L(2,-8)\), \(M(-1,-8)\)

Step2: Apply reflection formula

The formula for reflection over \(y = -x\) is \((x,y)\to(-y,-x)\)
For \(J(-9,-10)\): \((-y,-x)=(10,9)\)
For \(K(-6,-10)\): \((-y,-x)=(10,6)\)
For \(L(2,-8)\): \((-y,-x)=(8,-2)\)
For \(M(-1,-8)\): \((-y,-x)=(8,1)\)

Step3: Plot new points

Plot \(J'(10,9)\), \(K'(10,6)\), \(L'(8,-2)\), \(M'(8,1)\) and connect them to form the parallelogram.

Answer:

Plot the points \(J'(10,9)\), \(K'(10,6)\), \(L'(8,-2)\), \(M'(8,1)\) and connect them.