Question

graph the image of parallelogram efgh after a translation 10 units up.

Explanation:

Step1: Find the coordinates of original points

Assume \(E(2,-10)\), \(F(2,-6)\), \(G(8,0)\), \(H(8,-4)\)

Step2: Apply the translation rule

The translation rule for moving 10 units up is \((x,y)\to(x,y + 10)\)
For point \(E\): \((2,-10)\to(2,-10 + 10)=(2,0)\)
For point \(F\): \((2,-6)\to(2,-6+10)=(2,4)\)
For point \(G\): \((8,0)\to(8,0 + 10)=(8,10)\)
For point \(H\): \((8,-4)\to(8,-4 + 10)=(8,6)\)

Step3: Plot the new points

Plot \(E'(2,0)\), \(F'(2,4)\), \(G'(8,10)\), \(H'(8,6)\) on the coordinate - plane and connect them to form the parallelogram.

Answer:

Plot the points \((2,0)\), \((2,4)\), \((8,10)\), \((8,6)\) and connect them to get the translated parallelogram.