Question

graph the image of p(-9, -1) after a translation 1 unit up.

Explanation:

Step1: Recall translation rule

For a translation 1 unit up, the rule is \((x, y) \to (x, y + 1)\).

Step2: Apply to point \(P(-9, -1)\)

Substitute \(x = -9\) and \(y = -1\) into the rule. So \(y\)-coordinate becomes \(-1 + 1 = 0\), and \(x\)-coordinate remains \(-9\). The new point is \((-9, 0)\). To graph it, find the position with \(x = -9\) (9 units left of origin on x - axis) and \(y = 0\) (on the x - axis), then plot the point.

Answer:

The image of \(P(-9, -1)\) after translation 1 unit up is the point \((-9, 0)\), and it should be plotted at \(x=-9\), \(y = 0\) on the coordinate grid.