Question

graph the function $f(x) = -6x^2 - 1$.
plot the vertex. then plot another point on the parabola. if you make a mistake,
you can erase your parabola by selecting the second point and placing it on top of
the first.
(the coordinate system is shown with x-axis from -10 to 10 and f(x)-axis from -10 to 10, with grid lines.)

Explanation:

Step1: Identify vertex form

The function $f(x) = -6x^2 - 1$ is in the form $f(x)=ax^2+k$, where vertex is $(0,k)$.

Step2: Find vertex coordinates

For $k=-1$, vertex is $(0, -1)$.

Step3: Pick x, compute f(x)

Choose $x=1$: $f(1)=-6(1)^2 -1=-6-1=-7$. So point is $(1,-7)$.

Answer:

1. Plot the vertex at $(0, -1)$
2. Plot a second point at $(1, -7)$ (or $(-1, -7)$), then draw a downward-opening parabola passing through these points.