Question

graph the function.
$f(x)=\sqrt{x}-5$
plot four points on the graph of the function: the leftmost point and three additional points. then click on the graph - a - function button.

Explanation:

Step1: Find the domain

The expression under the square - root must be non - negative. So, $x\geq0$. The leftmost point occurs when $x = 0$.

Step2: Calculate the leftmost point

When $x = 0$, $f(0)=\sqrt{0}-5=- 5$. So the leftmost point is $(0, - 5)$.

Step3: Choose additional $x$ values

Let $x = 1$, then $f(1)=\sqrt{1}-5=1 - 5=-4$. The point is $(1,-4)$.
Let $x = 4$, then $f(4)=\sqrt{4}-5=2 - 5=-3$. The point is $(4,-3)$.
Let $x = 9$, then $f(9)=\sqrt{9}-5=3 - 5=-2$. The point is $(9,-2)$.

Answer:

The four points are $(0, - 5),(1,-4),(4,-3),(9,-2)$