Question

1. a glass marble has a mass of 18.5 g and a volume of 6.45 cm³.

a. determine the density of the marble.
b. what is the mass of six of these marbles? what is the volume? what is
the density?
c. how does the density of one marble compare with the density of six
of the marbles?

Explanation:

Part a

Step1: Recall density formula

Density ($
ho$) is defined as mass ($m$) divided by volume ($V$), so the formula is $
ho = \frac{m}{V}$.

Step2: Substitute values

Given $m = 18.5\ \text{g}$ and $V = 6.45\ \text{cm}^3$, substitute into the formula: $
ho=\frac{18.5}{6.45}$.

Step3: Calculate the value

$\frac{18.5}{6.45}\approx 2.87\ \text{g/cm}^3$.

Step1: Multiply mass of one by 6

Mass of one marble is $18.5\ \text{g}$, so mass of six is $m_{total}=18.5\times6$.

Step2: Calculate the product

$18.5\times6 = 111\ \text{g}$.

Step1: Multiply volume of one by 6

Volume of one marble is $6.45\ \text{cm}^3$, so volume of six is $V_{total}=6.45\times6$.

Step2: Calculate the product

$6.45\times6 = 38.7\ \text{cm}^3$.

Answer:

The density of the marble is approximately $2.87\ \text{g/cm}^3$.

Part b

Mass of six marbles: