Question

given right triangle jkl, what is the value of cos(l)?

Explanation:

Step1: Find hypotenuse

By Pythagorean theorem, $JL=\sqrt{12^{2}+5^{2}}=\sqrt{144 + 25}=\sqrt{169}=13$.

Step2: Use cosine definition

$\cos(L)=\frac{adjacent}{hypotenuse}=\frac{5}{13}$.

Answer:

$\frac{5}{13}$