QUESTION IMAGE
Question
- given that ps = 53.4, qt = 47.7, and qs = 53.4, find pq
2 given that m is perpendicular bisector of \\(\overline{pq}\\) and sq = 25.9, find sp
- given that m is perpendicular bisector of \\(\overline{pq}\\), ps = 4a, and qs = 2a + 26, find qs.
use the diagram to answer the questions below.
- given that \\(\overline{bd}\\) bisects \\(\angle abc\\) and cd = 21.9, find ad.
- given that ad = 61, cd = 61, and \\(m\angle abc = 48^\circ\\), find \\(m\angle cbd\\).
- given that da = cd, \\(m\angle dbc = (10x + 3)^\circ\\), and \\(m\angle dba = (8x + 10)^\circ\\), find \\(m\angle dbc\\).
Problem 1
Step1: Analyze triangle properties
Since \( PS = QS = 53.4 \), triangle \( PSQ \) is isosceles with \( PT = QT \) (as \( m \) is perpendicular to \( PQ \)).
Step2: Calculate \( PQ \)
\( PQ = 2\times QT = 2\times47.7 = 95.4 \)
Step1: Use perpendicular bisector property
A perpendicular bisector of a segment implies that any point on it is equidistant from the endpoints of the segment. So \( SP = SQ \).
Step2: Substitute \( SQ \) value
Given \( SQ = 25.9 \), so \( SP = 25.9 \)
Step1: Apply perpendicular bisector property
Since \( m \) is the perpendicular bisector of \( PQ \), \( PS = QS \). So \( 4a=2a + 26 \)
Step2: Solve for \( a \)
\( 4a-2a=26 \)
\( 2a = 26 \)
\( a = 13 \)
Step3: Calculate \( QS \)
Substitute \( a = 13 \) into \( QS = 2a + 26 \)
\( QS=2\times13 + 26=26 + 26 = 52 \)
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\( 95.4 \)