Question

given the mass of both blocks, what is the tension of the rope above the two blocks. (f1 the force holding both blocks up)

Explanation:

Step1: Calculate total mass

The total mass $m = 2.00\ kg+ 1.00\ kg=3.00\ kg$

Step2: Use Newton's second - law for equilibrium

In equilibrium, the tension $F_1$ in the rope above the two - block system balances the total weight. The weight formula is $W = mg$, where $g = 9.8\ m/s^{2}$. So $F_1=mg=(3.00\ kg)\times(9.8\ m/s^{2}) = 29.4\ N$

Answer:

29.4 N