Question

given the definition of func1, which of the following are valid ways to call func1? select all that apply.
def func1(x, y, z = 2):
if x - y < z:
return (x + y) * z
else:
return (x + y) / z
select all that apply
a func1(1,2)
b func1(1,2,3)
c func1(z=3)
d func1(z=3,y=2,x=1)

Explanation:

Step1: Analyze positional arguments

In Python, when calling a function, non - keyword (positional) arguments must be provided before keyword arguments. The function func1 has two required positional arguments x and y.

• For option A: func1(1,2) provides values for x = 1 and y = 2. Since z has a default value of 2, this is a valid call.
• For option B: func1(1,2,3) provides values for x = 1, y = 2 and z = 3. This is a valid call as it provides values for all parameters (using the default for none - provided is not needed here as all are provided).
• For option C: func1(z = 3) does not provide values for the required positional arguments x and y. This is an invalid call.
• For option D: func1(z = 3,y = 2,x = 1) uses keyword arguments. In Python, when using keyword arguments, the order of passing does not matter as long as all required arguments are provided. Here x = 1, y = 2 (required arguments) and z=3 (optional, overriding the default) are provided. This is a valid call.

Answer:

A. func1(1,2), B. func1(1,2,3), D. func1(z = 3,y = 2,x = 1)