Question

given \\((x - 7)^2 = 36\\), select the values of \\(x\\).

\\(x = 13\\)

\\(x = 1\\)

\\(x = -29\\)

\\(x = 42\\)

Explanation:

Step1: Take square root

$$x - 7 = \pm\sqrt{36}$$

Step2: Simplify square root

$$x - 7 = \pm 6$$

Step3: Solve first case

$$x = 7 + 6 = 13$$

Step4: Solve second case

$$x = 7 - 6 = 1$$

Answer:

\(x = 13\)
\(x = 1\)