QUESTION IMAGE
Question
- given: 2pq = pr
prove: q is the midpoint of \overline{pr}
| statements | reasons |
|---|---|
| 2. pr = pq + qr | 2. |
| 3. 2pq = pq + qr | 3. |
| 4. pq = qr | 4. |
| 5. | 5. def. of ________ |
(diagram: a line segment with points p, q, r in sequence)
Step1: Fill Statement 1
The given is \( 2PQ = PR \), so statement 1 is \( 2PQ = PR \).
Step2: Reason for Statement 2
The formula \( PR = PQ + QR \) is the Segment Addition Postulate (which states that if a point \( Q \) is between \( P \) and \( R \), then \( PR = PQ + QR \)). So reason 2 is "Segment Addition Postulate".
Step3: Reason for Statement 3
We substitute \( PR \) with \( 2PQ \) (from statement 1) into the equation from statement 2. So reason 3 is "Substitution Property (substituting \( PR \) with \( 2PQ \))".
Step4: Reason for Statement 4
Subtract \( PQ \) from both sides of \( 2PQ = PQ + QR \). Using the Subtraction Property of Equality (if \( a = b + c \), then \( a - b = c \)), we get \( PQ = QR \). So reason 4 is "Subtraction Property of Equality".
Step5: Fill Statement 5 and Reason
Since \( PQ = QR \), by the definition of a midpoint (a midpoint of a segment divides the segment into two congruent segments), \( Q \) is the midpoint of \( \overline{PR} \). So statement 5 is " \( Q \) is the midpoint of \( \overline{PR} \)" and reason 5 is "Def. of midpoint".
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- Statement 1: \( 2PQ = PR \)
- Reason 2: Segment Addition Postulate
- Reason 3: Substitution Property
- Reason 4: Subtraction Property of Equality
- Statement 5: \( Q \) is the midpoint of \( \overline{PR} \); Reason 5: Def. of midpoint