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given, ( p(e)=0.105 ), ( p(e cup f)=0.351 ), ( p(e cap f)=0.096 ), what…

Question

given, ( p(e)=0.105 ), ( p(e cup f)=0.351 ), ( p(e cap f)=0.096 ), what is ( p(f)=? ) note: enter your answer in the box below without rounding it.

Explanation:

Step1: Use the formula for the probability of the union of two events

The formula is \(P(E\cup F)=P(E)+P(F)-P(E\cap F)\).

Step2: Rearrange the formula to solve for \(P(F)\)

We get \(P(F)=P(E\cup F)+P(E\cap F)-P(E)\).

Step3: Substitute the given values

Substitute \(P(E) = 0.105\), \(P(E\cup F)=0.351\), and \(P(E\cap F)=0.096\) into the formula:
\(P(F)=0.351 + 0.096-0.105\).

Step4: Calculate the value

\(P(F)=0.342\).

Answer:

\(0.342\)