QUESTION IMAGE
Question
geometry
name
ws \triangle angle sum theorem\
date
find the measure of each angle indicated.
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Step1: Recall the triangle angle sum theorem
The sum of the interior angles of a triangle is \(180^{\circ}\). Let the unknown angle be \(x\). Then \(x + \text{known angle}_1+\text{known angle}_2 = 180^{\circ}\), so \(x=180^{\circ}-\text{known angle}_1 - \text{known angle}_2\)
Step2: Calculate each unknown angle
- \(x = 180^{\circ}-50^{\circ}-81^{\circ}=49^{\circ}\)
- \(x = 180^{\circ}-64^{\circ}-54^{\circ}=62^{\circ}\)
- \(x = 180^{\circ}-40^{\circ}-95^{\circ}=45^{\circ}\)
- \(x = 180^{\circ}-65^{\circ}-60^{\circ}=55^{\circ}\)
- \(x = 180^{\circ}-35^{\circ}-85^{\circ}=60^{\circ}\)
- \(x = 180^{\circ}-33^{\circ}-97^{\circ}=50^{\circ}\)
- \(x = 180^{\circ}-70^{\circ}-30^{\circ}=80^{\circ}\)
- \(x = 180^{\circ}-100^{\circ}-30^{\circ}=50^{\circ}\)
- \(x = 180^{\circ}-90^{\circ}-35^{\circ}=55^{\circ}\)
- \(x = 180^{\circ}-35^{\circ}-80^{\circ}=65^{\circ}\)
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- \(49^{\circ}\)
- \(62^{\circ}\)
- \(45^{\circ}\)
- \(55^{\circ}\)
- \(60^{\circ}\)
- \(50^{\circ}\)
- \(80^{\circ}\)
- \(50^{\circ}\)
- \(55^{\circ}\)
- \(65^{\circ}\)