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geometry find the possible values of x. the perimeter is less than 28 f…

Question

geometry find the possible values of x. the perimeter is less than 28 feet. 7 ft x 7 ft the possible values of x are 0 < 14.

Explanation:

Step1: Recall Perimeter Formula

The perimeter \( P \) of a triangle is the sum of its sides. For this isosceles triangle with two sides \( 7 \) ft and one side \( x \) ft, \( P = 7 + 7 + x = 14 + x \).

Step2: Apply Perimeter Inequality

We know the perimeter is less than \( 28 \) feet, so \( 14 + x < 28 \). Subtract \( 14 \) from both sides: \( x < 28 - 14 \), so \( x < 14 \).

Step3: Apply Triangle Inequality

For a triangle, the length of any side must be greater than \( 0 \) (since length can't be non - positive) and also, by the triangle inequality theorem, the sum of any two sides must be greater than the third side. Here, \( 7 + 7>x \) (which we already used for \( x < 14 \)) and \( 7 + x>7\) (which simplifies to \( x > 0 \)) and \( 7 + x>7\) (same as before). So combining, \( 0 < x < 14 \).

Answer:

The possible values of \( x \) are \( 0 < x < 14 \) (or in interval notation \( (0,14) \))