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geometric figure with dimensions 10 ft, 18 ft, 8 ft (appears to be a co…

Question

geometric figure with dimensions 10 ft, 18 ft, 8 ft (appears to be a composite shape, likely for area/perimeter calculation)

Explanation:

Step1: Analyze the figure (rectangle + trapezoid or rectangle - triangle)

The figure can be seen as a rectangle with length 18 ft and width 10 ft, minus a right triangle with base 10 ft and height 8 ft. First, find the area of the rectangle: $A_{rectangle} = length \times width = 18 \times 10$.

Step2: Calculate the area of the triangle

The area of a triangle is $\frac{1}{2} \times base \times height$. Here, base = 10 ft, height = 8 ft, so $A_{triangle} = \frac{1}{2} \times 10 \times 8$.

Step3: Subtract the triangle's area from the rectangle's area

$A = A_{rectangle} - A_{triangle} = 18\times10 - \frac{1}{2}\times10\times8$.
Calculate: $18\times10 = 180$, $\frac{1}{2}\times10\times8 = 40$, so $A = 180 - 40 = 140$.

Answer:

The area of the shaded region is 140 square feet.