Question

is the function $y = -\frac{1}{3}$ linear or nonlinear? linear nonlinear submit

Explanation:

Step1: Recall linear function form

A linear function is in the form \( y = mx + b \), where \( m \) (slope) and \( b \) (y - intercept) are constants, and \( x \) is the independent variable. If there's no \( x \) term, \( m = 0 \).

Step2: Analyze the given function

The function is \( y=-\frac{1}{3} \). We can rewrite it as \( y = 0x-\frac{1}{3} \). Here, \( m = 0 \) (slope) and \( b=-\frac{1}{3} \) (y - intercept), and it follows the form of a linear function (a horizontal line, which is a special case of a linear function with slope 0).

Answer:

linear