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four vehicles are on the road. rank them from greatest (1) to least (4)…

Question

four vehicles are on the road. rank them from greatest (1) to least (4) kinetic energy.
mass: 4m
velocity: 0
mass: m
velocity: v
mass: 2m
velocity: v
mass: m
velocity: 2v

Explanation:

Step1: Recall Kinetic Energy Formula

The formula for kinetic energy (KE) is \( KE = \frac{1}{2}mv^2 \), where \( m \) is mass and \( v \) is velocity.

Step2: Calculate KE for Each Vehicle

  • Vehicle 1 (Mass: \( 4m \), Velocity: \( 0 \)):

Substitute into the formula: \( KE_1 = \frac{1}{2}(4m)(0)^2 = 0 \).

  • Vehicle 2 (Mass: \( m \), Velocity: \( v \)):

Substitute: \( KE_2 = \frac{1}{2}(m)(v)^2 = \frac{1}{2}mv^2 \).

  • Vehicle 3 (Mass: \( 2m \), Velocity: \( v \)):

Substitute: \( KE_3 = \frac{1}{2}(2m)(v)^2 = mv^2 \).

  • Vehicle 4 (Mass: \( m \), Velocity: \( 2v \)):

Substitute: \( KE_4 = \frac{1}{2}(m)(2v)^2 = \frac{1}{2}(m)(4v^2) = 2mv^2 \).

Step3: Rank by KE Magnitude

Compare the calculated KE values:
\( KE_4 = 2mv^2 \) (greatest) > \( KE_3 = mv^2 \) > \( KE_2 = \frac{1}{2}mv^2 \) > \( KE_1 = 0 \) (least).

So the ranking from greatest (1) to least (4) is:

  1. Vehicle 4 (Mass: \( m \), Velocity: \( 2v \))
  2. Vehicle 3 (Mass: \( 2m \), Velocity: \( v \))
  3. Vehicle 2 (Mass: \( m \), Velocity: \( v \))
  4. Vehicle 1 (Mass: \( 4m \), Velocity: \( 0 \))

Answer:

  1. Mass: \( m \), Velocity: \( 2v \)
  2. Mass: \( 2m \), Velocity: \( v \)
  3. Mass: \( m \), Velocity: \( v \)
  4. Mass: \( 4m \), Velocity: \( 0 \)