Question

6 formula 1 point a mass of 0.3 kilograms is hung from a vertical spring causing the spring to stretch a distance of 0.7 meters from its equilibrium position. calculate the spring constant of the spring. remember that the spring constant is always a positive number answer previous submit

Explanation:

Step1: Calculate the force exerted by the mass

The force \(F\) due to the mass \(m\) is given by \(F = mg\), where \(g = 9.8\ m/s^{2}\) (acceleration due to gravity).
\(F=0.3\times9.8 = 2.94\ N\)

Step2: Use Hooke's Law to find the spring constant

Hooke's Law is \(F=kx\), where \(k\) is the spring constant and \(x\) is the displacement. We need to solve for \(k\), so \(k=\frac{F}{x}\).
Given \(x = 0.7\ m\) and \(F = 2.94\ N\), then \(k=\frac{2.94}{0.7}\)
\(k = 4.2\ N/m\)

Answer:

\(4.2\)