Question

the formula for aluminum nitrate is al(no₃)₃. how many total atoms are in 4 molecules of aluminum nitrate? aluminum type your answer... nitrogen type your answer... oxygen type your answer... total atoms type your answer...

Explanation:

Step1: Analyze atoms in one molecule

In \( \text{Al(NO}_3\text{)}_3 \), there is \( 1 \) Al atom. For N: \( 1\times3 = 3 \) N atoms (from \( 3 \) \( \text{NO}_3 \) groups). For O: \( 3\times3=9 \) O atoms (since each \( \text{NO}_3 \) has \( 3 \) O atoms).

Step2: Multiply by the number of molecules (\( n = 4 \))

For Al: \( 1\times4=4 \)
For N: \( 3\times4 = 12 \)
For O: \( 9\times4=36 \)
For total atoms: \( (1 + 3+9)\times4=(13)\times4 = 52 \)

Answer:

Aluminum: \( 4 \)
Nitrogen: \( 12 \)
Oxygen: \( 36 \)
Total atoms: \( 52 \)