Question

the force that results from all the combined forces acting on the object is called the net force. calculate the net force acting on the box in the following problems. be sure to include the direction of the net force (left or right)! 1. net force: 2. net force: 3. net force: 4. net force: 5. net force: 6. net force: 7. net force: 8. net force: 9. net force: 10. net force:

Explanation:

Step1: Define the direction of forces

Let's assume the right - hand direction as positive and the left - hand direction as negative.

Step2: Calculate net force for each problem

Problem 1

There is a single force of \(F=- 4N\) (left - hand direction). So, the net force \(F_{net}=-4N\) (left).

Problem 2

Forces are \(F_1=-7N\) (left) and \(F_2 = 2N\) (right). Using the formula \(F_{net}=F_1 + F_2\), we get \(F_{net}=-7 + 2=-5N\) (left).

Problem 3

Forces are \(F_1 = 4N\) (right) and \(F_2=-4N\) (left). \(F_{net}=4+( - 4)=0N\) (no net force direction as magnitude is zero).

Problem 4

Forces are \(F_1 = 6N\) (right) and \(F_2 = 3N\) (right). \(F_{net}=6 + 3=9N\) (right).

Problem 5

Forces are \(F_1=-8N\) (left) and \(F_2 = 4N\) (right). \(F_{net}=-8 + 4=-4N\) (left).

Problem 6

Forces are \(F_1 = 4N\) (right) and \(F_2=-5N\) (left). \(F_{net}=4+( - 5)=-1N\) (left).

Problem 7

Forces are \(F_1=-3N\) (left) and \(F_2=-3N\) (left). \(F_{net}=-3+( - 3)=-6N\) (left).

Problem 8

Forces are \(F_1 = 2N\) (right), \(F_2 = 4N\) (right) and \(F_3=-5N\) (left). \(F_{net}=2 + 4+( - 5)=1N\) (right).

Problem 9

Forces are \(F_1=-6N\) (left) and \(F_2 = 3N\) (right). \(F_{net}=-6 + 3=-3N\) (left).

Problem 10

Forces are \(F_1=-7N\) (left), \(F_2 = 4N\) (right) and \(F_3 = 4N\) (right). \(F_{net}=-7+4 + 4=1N\) (right).

Answer:

1. \(4N\) (left)
2. \(5N\) (left)
3. \(0N\)
4. \(9N\) (right)
5. \(4N\) (left)
6. \(1N\) (left)
7. \(6N\) (left)
8. \(1N\) (right)
9. \(3N\) (left)
10. \(1N\) (right)