Question

1. the force of the balloon pushing on the air is (greater than - less than - equal to) the force of the air pushing on the balloon. the resulting acceleration of the more massive balloon is (greater than - less than - equal to) the resulting acceleration of the less massive air.

Explanation:

Step1: Apply Newton's third law

Newton's third law states that for every action, there is an equal and opposite reaction. So, the force of the balloon pushing on the air is equal to the force of the air pushing on the balloon.

Step2: Apply Newton's second law \(F = ma\) (where \(F\) is force, \(m\) is mass, and \(a\) is acceleration)

We can rewrite it as \(a=\frac{F}{m}\). Since \(F\) (the force) is the same for both the balloon and the air (from step 1), and the mass of the balloon (\(m_{balloon}\)) is greater than the mass of the air (\(m_{air}\)) (\(m_{balloon}>m_{air}\)), when we calculate the acceleration \(a\). For the balloon \(a_{balloon}=\frac{F}{m_{balloon}}\) and for the air \(a_{air}=\frac{F}{m_{air}}\). Since the denominator \(m_{balloon}>m_{air}\), the resulting acceleration of the more - massive balloon is less than the resulting acceleration of the less - massive air.

Answer:

equal to; less than