Question

a football is kicked vertically upward from a height of 3 feet with an initial speed of 70 feet per second. the formula h = 3 + 70t - 16t^2 describes the balls height above the ground, h, in feet, t seconds after it was kicked. use this formula to find the balls height 2 seconds after it was kicked. the balls height, 2 seconds after it was kicked, was feet.

Explanation:

Step1: Substitute t value

Substitute $t = 2$ into $h=3 + 70t-16t^{2}$.
$h=3 + 70\times2-16\times2^{2}$

Step2: Calculate multiplications

Calculate $70\times2$ and $16\times2^{2}$.
$70\times2 = 140$, $16\times2^{2}=16\times4 = 64$.
So $h=3 + 140-64$.

Step3: Calculate addition and subtraction

$h=(3 + 140)-64=143-64 = 79$.

Answer:

79