Question

for the following right triangle, find the side length x. round your answer to the nearest hundredth.

Explanation:

Step1: Apply Pythagorean theorem

In a right - triangle, \(a^{2}+b^{2}=c^{2}\), where \(a = 11\), \(b = 10\) and \(c=x\). So \(x^{2}=11^{2}+10^{2}\).

Step2: Calculate \(11^{2}\) and \(10^{2}\)

\(11^{2}=121\), \(10^{2}=100\). Then \(x^{2}=121 + 100=221\).

Step3: Solve for \(x\)

\(x=\sqrt{221}\approx14.87\)

Answer:

\(14.87\)