Question

the following formula gives the area a of a trapezoid with base lengths $b_1$ and $b_2$, and height $h$.
$a = \frac{1}{2}(b_1 + b_2)h$
find the area of a trapezoid with base lengths 6 and 4 and a height of 5.
select the correct answer below:
\bigcirc 22
\bigcirc 27
\bigcirc 26
\bigcirc 31
\bigcirc 17
\bigcirc 25

Explanation:

Step1: Substitute the values into the formula

Given \(b_1 = 6\), \(b_2=4\), \(h = 5\). Substitute into \(A=\frac{1}{2}(b_1 + b_2)h\), we get \(A=\frac{1}{2}(6 + 4)\times5\).

Step2: Calculate the sum of the bases

First, calculate \(6 + 4=10\). Then the formula becomes \(A=\frac{1}{2}\times10\times5\).

Step3: Calculate the area

\(\frac{1}{2}\times10 = 5\), and \(5\times5=25\).

Answer:

\(25\)