Question

the floor inside a bathtub slopes down at a 1.2° angle toward the drain. the horizontal distance from the far end of the bathtub floor to the drain is 5 feet. what is the total distance, in inches, the water travels from the far end of the bathtub floor to the drain? choose 1 answer: a 12·5/sin(1.2°) b 12·5/cos(1.2°) c 12·5 (sin(1.2°)) d 12·5 (cos(1.2°))

Explanation:

Step1: Convert feet to inches

Since \(1\) foot \( = 12\) inches, then \(5\) feet \(=12\times5\) inches.

Step2: Use cosine function

In a right - triangle, \(\cos\theta=\frac{\text{adjacent}}{\text{hypotenuse}}\). Here, \(\theta = 1.2^{\circ}\), the adjacent side (horizontal distance) is \(12\times5\) inches and the hypotenuse is the distance water travels (let's call it \(d\)). So, \(\cos(1.2^{\circ})=\frac{12\times5}{d}\), and solving for \(d\) gives \(d = \frac{12\times5}{\cos(1.2^{\circ})}\).

Answer:

B. \(\frac{12\cdot5}{\cos(1.2^{\circ})}\)