Question

a flexible container originally has a volume of 17 l and holds 0.75 mol ne. additional ne is added, giving a total of 1.25 mol ne. the temperature and pressure are constant. what is the new volume? v₂ = ? l

Explanation:

Step1: Apply Avogadro's Law

$\frac{V_1}{n_1} = \frac{V_2}{n_2}$
Given $V_1=17\ \text{L}$, $n_1=0.75\ \text{mol}$, $n_2=1.25\ \text{mol}$

Step2: Solve for $V_2$

$V_2 = V_1 \times \frac{n_2}{n_1}$
$V_2 = 17\ \text{L} \times \frac{1.25}{0.75}$

Step3: Calculate the value

$V_2 = 17 \times \frac{5}{3} \approx 28.33\ \text{L}$

Answer:

28.33 L (or $\frac{85}{3}$ L)