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finding the factors of a trinomial what are the factors of \\(x^2 - 4x …

Question

finding the factors of a trinomial

what are the factors of \\(x^2 - 4x - 5\\)? check all that apply.

\\(x - 5\\)
\\(x - 2\\)
\\(x - 1\\)
\\(x + 1\\)
\\(x + 2\\)
\\(x + 5\\)

Explanation:

Identify the trinomial to factor

The given trinomial is:

$$ x^2 - 4x - 5 $$

Find two numbers that multiply to \(ac\) and add to \(b\)

For the quadratic expression \(ax^2 + bx + c\), we have \(a = 1\), \(b = -4\), and \(c = -5\).
We need two integers whose product is \(a \cdot c = -5\) and whose sum is \(b = -4\).
The factors of \(-5\) are:

$$ LATEXBLOCK0 $$

The correct pair is \(-5\) and \(1\).

Write the factored form

Using the found integers, we write the trinomial in its factored form:

$$ x^2 - 4x - 5 = (x - 5)(x + 1) $$

Thus, the factors are \(x - 5\) and \(x + 1\).

Answer:

  • (A) \(x - 5\) (Correct answer)
  • (B) \(x - 2\)
  • (C) \(x - 1\)
  • (D) \(x + 1\) (Correct answer)
  • (E) \(x + 2\)
  • (F) \(x + 5\)