Question

find the value of x in the triangle shown below. choose 1 answer. x = √61 x = √11 do 7 problems 0 0 0 0 0

Explanation:

Step1: Apply Pythagorean theorem

For a right - triangle with sides \(a\), \(b\), and hypotenuse \(c\), \(a^{2}+b^{2}=c^{2}\). Here, \(c = 6\), \(b = 5\), and \(a=x\). So \(x^{2}+5^{2}=6^{2}\).

Step2: Solve for \(x^{2}\)

\(x^{2}=6^{2}-5^{2}\). Since \(6^{2}=36\) and \(5^{2}=25\), then \(x^{2}=36 - 25=11\).

Step3: Solve for \(x\)

\(x=\sqrt{11}\) (we take the positive square root as \(x\) represents the length of a side of a triangle).

Answer:

\(x = \sqrt{11}\)