Question

find the value of $x$ in the triangle shown below.
$x = square^{circ}$

Explanation:

Step1: Use the property of isosceles triangle

In an isosceles triangle, the angles opposite to equal sides are equal. Here, two sides are \(6.2\), so the angles opposite to them are equal. Let the third angle be \(x\).

Step2: Use the angle - sum property of a triangle

The sum of angles in a triangle is \(180^{\circ}\). Let the two equal angles be \(x\) (the one we need to find) and the third angle is \(61^{\circ}\). So, \(x + x+61^{\circ}=180^{\circ}\).
Simplify the equation: \(2x=180^{\circ}- 61^{\circ}\).
\(2x = 119^{\circ}\).
Then \(x=\frac{119^{\circ}}{2}\).

Answer:

\(59.5\)