Question

find the value of c. pythagorean theorem: a² + b² = c² 10 in 11 in c = √?

Explanation:

Step1: Identify values for a and b

Let $a = 10$ and $b = 11$.

Step2: Apply Pythagorean theorem

According to $a^{2}+b^{2}=c^{2}$, we substitute the values: $c^{2}=10^{2}+11^{2}$.
Calculate $10^{2}=100$ and $11^{2}=121$. Then $c^{2}=100 + 121=221$.

Step3: Solve for c

Since $c^{2}=221$, then $c=\sqrt{221}$.

Answer:

$\sqrt{221}$