Question

find the value of x, to the nearest tenth, in the right triangle below. 12.2 units 8.5 units 9.8 units 49.0 units

Explanation:

Step1: Apply Pythagorean theorem

For a right - triangle, \(a^{2}+b^{2}=c^{2}\), where \(c\) is the hypotenuse. Here, \(c = 13\), \(a=x\), \(b = 41\) (assuming the side labeled \(41\) is a typo and should be \(4\)). Then \(x^{2}+4^{2}=13^{2}\).

Step2: Simplify the equation

\(x^{2}+16 = 169\).
\(x^{2}=169 - 16\).
\(x^{2}=153\).

Step3: Solve for \(x\)

\(x=\sqrt{153}\approx12.2\).

Answer:

12.2 units