QUESTION IMAGE
Question
find the value of the expression.
\\\frac{5(2^2 - 1) + 17}{6 - 2^2}\\
\\\frac{5(2^2 - 1) + 17}{6 - 2^2} = \square\\ (type an integer or a simplified fraction.)
Evaluate exponential terms
$$
2^2 = 4
$$
Simplify the numerator and denominator
$$
LATEXBLOCK0
$$
Divide the numerator by the denominator
$$
\frac{32}{2} = 16
$$
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\(\frac{5(2^2 - 1) + 17}{6 - 2^2} =\) <blank>16</blank>