Question

find the sum:
$6\frac{1}{10} + 1\frac{11}{30}$

Explanation:

Step1: Convert mixed numbers to improper fractions

$6\frac{1}{10} = \frac{6\times10 +1}{10}=\frac{61}{10}$, $1\frac{11}{30}=\frac{1\times30+11}{30}=\frac{41}{30}$

Step2: Find common denominator and add

$\frac{61}{10} = \frac{61\times3}{30}=\frac{183}{30}$
$\frac{183}{30}+\frac{41}{30}=\frac{183+41}{30}=\frac{224}{30}$

Step3: Simplify and convert back to mixed number

$\frac{224}{30}=\frac{112}{15}=7\frac{7}{15}$

Answer:

$7\frac{7}{15}$